Answer:
The answer is "164.2726 g "
Explanation:
Equation:
The molar weight of
The mol in
The molar weight of
The moles in
The ratio in the equation is 3:1 so, limits reaction the ratio is 3:1 therefore, 0.392456 mol of were reacted
The molar mass of the
[tex]mass= mol \times Molar \ Weight[/tex]
[tex]= 418.576 \times 0.392456 \\\\= 164.2726 \ g \ of \ Ag_3PO_4[/tex]
