The given question is incomplete. The complete question is:
A force of 90 Newton's is applied to a [tex]20cm^2[/tex] surface. The force applied is then increased by 5 Newton's and the surface is increased by [tex]5cm^2[/tex]. What percentage does the outcome decrease by
Answer: The outcome decreases by 15.5 %
Step-by-step explanation:
Pressure is defined as the ratio of force per unit area.
[tex]Pressure=\frac{Force}{Area}[/tex]
Case 1: [tex]P_1=\frac{90N}{20cm^2}=4.5Ncm^{-2}[/tex]
Case 2: [tex]P_2=\frac{95N}{25cm^2}=3.8Ncm^{-2}[/tex]
Decrease in pressure = [tex]P_1-P_2[/tex] = [tex](4.5-3.8) Ncm^{-2}=0.7Ncm^{-2}[/tex]
Percentage decrease = [tex]\frac{0.7}{4.5}\times 100\%=15.5\%[/tex]
Thus the outcome decreases by 15.5 %
