Answer:
The other factors are: [tex](x-2)[/tex] and [tex](x^2+2x+4)[/tex]
Step-by-step explanation:
Given
Polynomial: [tex]x^4 + 2x^3 - 8x - 16[/tex]
Factor: [tex]x + 2[/tex]
Required
Find other factors
[tex]x^4 + 2x^3 - 8x - 16[/tex]
Group into two
[tex]x^4 + 2x^3 - 8x - 16 = (x^4 + 2x^3) - (8x + 16)[/tex]
Factorize:
[tex]x^4 + 2x^3 - 8x - 16 = x^3(x + 2) -8 (x + 2)[/tex]
Factor out common term
[tex]x^4 + 2x^3 - 8x - 16 = (x^3 -8)(x + 2)[/tex]
Rewrite [tex]x^3- 8[/tex] as [tex]x^3 + 2x^2 - 2x^2+ 4x - 4x - 8[/tex]
[tex]x^4 + 2x^3 - 8x - 16 = (x^3 + 2x^2 - 2x^2+ 4x - 4x - 8)(x + 2)[/tex]
Rearrange the terms
[tex]x^4 + 2x^3 - 8x - 16 = (x^3 + 2x^2 + 4x - 2x^2 - 4x - 8)(x + 2)[/tex]
Factorize
[tex]x^4 + 2x^3 - 8x - 16 = (x(x^2+2x+4)-2(x^2+2x+4))(x + 2)[/tex]
Factor out [tex](x^2+2x+4)[/tex]
[tex]x^4 + 2x^3 - 8x - 16 = (x-2)(x^2+2x+4)(x + 2)[/tex]
So, the other factors are: [tex](x-2)[/tex] and [tex](x^2+2x+4)[/tex]
