Answer:
a) E = 1.06 10⁻¹⁹ J, b) v = 9.78 10⁵ m / s
Explanation:
The physical magnitudes can be given in several units, but in general all must be reduced to the same system in a given exercise, the most used system is the international (SI)
1 eV =q V= 1.6 10⁻¹⁹ J
let's reduce the quantities requested
a) E = 1.0 eV to Joule
E = 1.0 eV (1.6 10⁻¹⁹ J / 1 eV)
E = 1.06 10⁻¹⁹ J
b) the kinetic energy is given by
K = ½ m v²
v = [tex]\sqrt{\frac{2K}{m} }[/tex]
the mass of the proton is
m = 1,673 10⁻²⁷ kg
let's reduce the energy to the SI system
E = 5000 ev (1.6 10-19 J / 1 eV) = 8000 10⁻¹⁹ J
let's calculate
v = [tex]\sqrt{ \frac{2 \ 8000 \ 10^{-19}}{1.673 \ 10^{-27} } }[/tex]
v = [tex]\sqrt{ 95.637 \ 10^{10} }[/tex]
v = 9.78 10⁵ m / s
