Answer:
(370-2x)ml
Step-by-step explanation:
We are given that
In first hand sanitizer
Total solution=200ml
Alcohol=15% of 200ml
Alcohol=[tex]\frac{15}{100}\times 200=30ml[/tex]
In second hand sanitizer
Solution=200 ml
Alcohol=x% of 200 ml
Alcohol=[tex]\frac{x}{100}\times 200=2x ml[/tex]
We have to find the water in the resulting mixture of hand sanitizers.
Total solution of two hand sanitizers=200+200=400ml
Total alcohol in two hand sanitizers=(30+2x)ml
Water in two hand sanitizers=400-(30+2x) ml
Water in two hand sanitizers=400-30-2x ml
Water in two hand sanitizers=(370-2x)ml
Hence, water in the resulting mixture of hand sanitizers=(370-2x)ml
