Answer:
[tex]d=2.15g/mL[/tex]
Explanation:
Hello there!
In this case, since the density of the metal is computed as shown below:
[tex]d=\frac{m}{V}[/tex]
We need to calculate the volume of the solid by subtracting the final volume and the initial volume of water:
[tex]V=54.10mL-45.50mL\\\\V=8.60mL[/tex]
Thus, we obtain:
[tex]d=\frac{18.5g}{8.60mL}\\\\d=2.15g/mL[/tex]
Best regards!