Given:
The two functions are
[tex]f(x)=3x+1[/tex]
[tex]g(x)=x^2-6[/tex]
To find:
The function (f+g)(x).
Solution:
We know that,
[tex](f+g)(x)=f(x)+g(x)[/tex]
Putting the values of given functions, we get
[tex](f+g)(x)=3x+1+x^2-6[/tex]
[tex](f+g)(x)=x^2+3x+(1-6)[/tex]
[tex](f+g)(x)=x^2+3x-5[/tex]
Therefore, the required function is [tex](f+g)(x)=x^2+3x-5[/tex].
