Answer:
The model is [tex]P(t) = 2000(1.075)^{t}[/tex].
There will be 4122 fish in 10 years.
Step-by-step explanation:
Exponentially increasing population:
An exponentially increasing population can be represented by the following model:
[tex]P(t) = P(0)(1+r)^t[/tex]
In which P(t) is the population after t years, P(0) is the initial population, and r is the growth rate, as a decimal.
A population of 2000 fish increases at an annual rate of 7.5%.
This means that [tex]P(0) = 2000, r = 0.075[/tex]
So
[tex]P(t) = P(0)(1+r)^t[/tex]
[tex]P(t) = 2000(1+0.075)^t[/tex]
[tex]P(t) = 2000(1.075)^{t}[/tex]
This is the model.
How many fish will there be in 10 years?
This is P(10).
[tex]P(t) = 2000(1.075)^{t}[/tex]
[tex]P(10) = 2000(1.075)^{10} = 4122[/tex]
There will be 4122 fish in 10 years.
