Given:
A line passing through point (2,5) with gradient 3.
To find:
The equation of the line.
Solution:
Point slope form: if a line passes through the point [tex](x_1,y_1)[/tex] and m is the slope or gradient, then the equation of line is
[tex]y-y_1=m(x-x_1)[/tex]
[tex]y-5=3(x-2)[/tex]
[tex]y-5=3(x)+3(-2)[/tex]
[tex]y-5=3x-6[/tex]
Adding 5 on both sides, we get
[tex]y=3x-6+5[/tex]
[tex]y=3x-1[/tex]
Therefore, the equation of the line is [tex]y=3x-1[/tex].
