What is the final, balanced equation that is formed by combining these two half reactions? 2 equations: first: upper C u right arrow upper C u superscript 2 plus, plus 2 e superscript minus. Second: upper N upper O subscript 3 superscript minus, plus 2 e superscript minus, plus 2 upper H superscript plus right arrow upper n upper O subscript 2 superscript minus plus upper H subscript 2 upper O.

Respuesta :

Answer: [tex]Cu+NO_3^-+2H^+\rightarrow Cu^{2+}+NO_2^-+H_2O[/tex]

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

[tex]Cu\rightarrow Cu^{2+}+2e^-[/tex]     (1)

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

[tex]NO_3^-+2e^-+2H^+\rightarrow NO_2^-+H_2O[/tex]    (2)

Combining (1) and (2) we get:

[tex]Cu+NO_3^-+2H^+\rightarrow Cu^{2+}+NO_2^-+H_2O[/tex]

The balanced reaction equation for the reaction described in the question is; Cu + NO3^- + 2H^+ ------> Cu^2+ + NO2^- + H2O

What is a balanced reaction equation?

An equation is said to be balanced when the total number of atoms of each element on the right hand side of the reaction equation is equal to the total number of atoms of the same element on the left hand side of the reaction equation.

The balanced reaction equation for the reaction described in the question is; Cu + NO3^- + 2H^+ ------> Cu^2+ + NO2^- + H2O

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