Answer:
4.2 m/s
the balls final speed is V (m/s)
because the clay ball hits another and the two stick together
=> 0,35.4,2 + 0,35.4,2 = (0,35 + 0,35).V
<=> 2,94 = 0,7V
<=> V = 2,94/0,7 = 4,2
For a clay ball with a mass of 0.35 kg, the ball's final speed is mathematically given as
V2= 4.2
Question Parameter(s):
A clay ball with a mass of 0.35 kg
Hits another 0.35 kg ball at rest and the two stick together.
The first ball's initial speed is 4.2m/s.
Generally, the equation for the conservation of momentum is mathematically given as
M1v1=m2v2
Therefore
0.35*4.2 + 0.3*5.4.2 = (0.35 + 0.35)*V
2,94 = 0,.7V
V2 = 2.94/0.7
V2 = 4.2
In conclusion
V2= 4.2
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