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What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)?

A. (x + 2)2 + (y + 3)2 = 9

B. (x − 2)2 + (y − 3)2 = 16

C. (x − 2)2 + (y − 3)2 = 4

D. (x + 2)2 + (y + 3)2 = 16

E. (x − 2)2 + (y + 3)2 = 9

Respuesta :

imtiazkalwar

Answer:

A.  [tex](x+2)^2 + (y+3)^2 = 9[/tex]

Step-by-step explanation:

Equation of a circle is

[tex](x-x_1)^2+(y-y_1)^2=r^2[/tex]    ------------- (1)

Here

[tex](x_1, y_1) = (-2, -3)[/tex]

Radius is distance from center to circumference

[tex]r=\sqrt{(-2+2)^2+(-3-0)^2}[/tex]

[tex]r=3[/tex]

Substituting values in equation (1)

[tex](x+2)^2 + (y+3)^2 = 9[/tex]

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