A shark is swimming 42 feet below sea level. If the angle of depression from a boat on the water to the shark is 23°, what is the horizontal distance between the boat and the shark? Show your work to receive full credit. Round to the nearest hundredth if necessary. ​

A shark is swimming 42 feet below sea level If the angle of depression from a boat on the water to the shark is 23 what is the horizontal distance between the b class=

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Answer:

BC ≈ 98.95 feet

Step-by-step explanation:

From the figure attached,

A shark is swimming 42 feet below sea level at point A and a boat on the water is at point C.

If the angle of depression from the coat to shark is 23°,

tan(23°) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]

tan(23°) = [tex]\frac{AB}{BC}[/tex]

BC = [tex]\frac{AB}{\text{tan}(23)}[/tex]

BC = [tex]\frac{42}{\text{tan}23}[/tex]

BC = 98.947

BC ≈ 98.95 feet

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