A police car is moving east at 20m/s towards a driver who is moving west at 25m/s. The police car emits a frequency of 900Hz. What frequency is detected by the driver? The speed of sound at the time of this occurrence was 343m/s.

Respuesta :

Answer:

f = 2445 Hz

Explanation:

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Lanuel

The frequency that the driver (observer) detects is equal to 1008 Hz

Given the following data:

  • Observer velocity = 25.0 m/s
  • Frequency of sound = 900 Hz
  • Source velocity = 20.0 m/s
  • Speed of sound = 343 m/s

To calculate the frequency that the driver (observer) detects, we would apply Doppler's effect of sound waves:

Mathematically, Doppler's effect of sound waves is given by the formula:

[tex]F_o = \frac{V \;+ \;V_o}{V\; - \;V_s} F[/tex]

Where:

  • V is the speed of a sound wave.
  • F is the actual frequency of sound.
  • [tex]V_o[/tex] is the observer velocity.
  • [tex]V_s[/tex] is the source velocity.
  • [tex]F_o[/tex] is the observer frequency.

Substituting the given parameters into the formula, we have;

[tex]F_o = \frac{343 \;+ \;20}{343\; - \;20} \times 900\\\\F_o = \frac{363}{323} \times 900\\\\F_o = 1.12 \times 900\\\\F_o =1008 \;Hz[/tex]

Driver (observer) frequency = 1008 Hz

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