Respuesta :

Answer:

50%

Explanation:

Make a punnet square

     Xn  Xn

XN XNXn XNXn

Y   XnY XnY

Colorblind is a recessive trait (n) so the fraction is 2/4

luisvaschetto

If a colorblind female (XnXn) and a normal male (XNY) have a son, then the chances he would be colorblind is 50%.

  • Inheritance linked to the X chromosome is different from the inheritance of autonomic chromosomes because males inherit only one X chromosome.

  • Conversely, females inherit two X chromosomes, thereby resembling mendelian autonomic inheritance.

  • In the Punnet square:

          Xn           Xn

XN   XNXn        XNXn

Y       XnY           XnY

In conclusion, if a colorblind female (XnXn) and a normal male (XNY) have a son, then the chances he would be colorblind is 50%.

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