Answer:
Neither
Step-by-step explanation:
If f (–x) = f (x), then the function is even. if f (–x) = –f (x), (all the signs are flipped) the it is odd.
To apply this to the function here, simply replace the x in [tex](x-2)^{2}[/tex] with -x.
[tex](x-2)^{2}[/tex] = [tex]x^{2}[/tex] - 4x + 4, and [tex](-x - 2)^{2}[/tex] = [tex]x^{2}[/tex] +4x + 4.
Since [tex]x^{2}[/tex]+4x + 4 doesnt equal [tex]x^{2}[/tex] - 4x + 4 (even) or [tex]-x^{2}[/tex]+4x -4 (odd), the function is neither even nor odd.
