The students in Ms. Douglas’ class worked so hard this year that she has planned a surprise, end-of -year trip for them to a local amusement park. The school principal allows Ms. Douglas to spend a budget of $500 on the trip.
So far she knows :
A coach bus costs $180 to transport them to and from the park.
Price of admission to the park is $15 per person

Part A : Write an inequality that describes that how many students Ms. Douglas can bring on the trip. Define the variable

Part B: Solve the inequality and explain the solution in the context o the problem

So in part A since you have 500 to spend and 180 goes to the coach bus, you are left with $ 320 to spend on the students and when you divide 320 by 15, (since the tickets for admission are $15) you end up with 21.333, but since you cant bring .333 of a student on a trip you can bring 21 students, but you can buy 21.333 tickets.

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yanc14 yanc14 · Answer 2 · 2021-02-09T23:13:16+01:00

yanc14 yanc14

09-02-2021

Answer:
A) 15x+180 ≤ 500
B) 33 people can go on the trip to not exceed the budget.

Steps:

15x+180 ≤500
Subtract 180 from both sides

15x ≤ 500
Divide both sides by 15 to isolate x(make sure to flip the sign since you are multiplying)

x ≥ 33.333

Therefore, only 33 people can go on the trip to not exceed the budget.

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