Find the 18h term of the arithmetic sequence whose common difference is d=4 and whose first term is a, =3.

Answer:
the 18th term is 71
Step-by-step explanation:
The general form for any term "n" in an arithmetic sequence is:
a(n) = a1 + (n-1) * d
where "d" is the common difference.
So, in our case we have:
a(n) = 3 + (n-1) *4
Therefore, the 18th term will be:
a(18) = 3 + (18 - 1) 4 = 3 + 17 * 4 = 71