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A diver jumps from a platform diving board that is 32 feet above water. The height , h of the diver above water , in feet, t seconds after jumping from the platform , can be determined by the equation h=-16t^2+20t+32. Determine the diver's height above water 2 seconds after jumping from the platform.
CAN SOMEONE HELP ME OUT PLEASE!!!!!!!!!!

Respuesta :

Answer:

h=8

Step-by-step explanation:

h = -16t^2 + 20t + 32

h = -16(2)^2 + 20(2) + 32

h = -16(4) + 40 + 32

h = -64 + 72

h = 8

guardadoademari

Answer:

2 seconds

Step-by-step explanation:

i got it right, no explanation <3

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