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If the initial temperature of a movable cylinder was 130 degrees Celsius
with a pressure of 1 ATM and an initial volume of 2 Liters, what would
the new volume be if the temperature was lowered to 324 degrees Kelvin
and the pressure was raised to 1.1 ATM?

Respuesta :

Answer: The new volume will be 1.5 L

Explanation:

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 1 atm

[tex]P_2[/tex] = final pressure of gas = 1.1 atm

[tex]V_1[/tex] = initial volume of gas = 2 L

[tex]V_2[/tex] = final volume of gas = ?

[tex]T_1[/tex] = initial temperature of gas = [tex]130^0C=(130+273)K=403K[/tex]

[tex]T_2[/tex] = final temperature of gas = [tex]324K[/tex]

Now put all the given values in the above equation, we get:

[tex]\frac{1\times 2}{403}=\frac{1.1\times V_2}{324}[/tex]

[tex]V_2=1.5L[/tex]

The new volume will be 1.5 L

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