Given;
The figure of a right angle triangle.
To find:
The value of x.
Solution:
In a right angle triangle,
[tex]\cos \theta=\dfrac{Adjacent}{Hypotenuse}[/tex]
In the given right angle triangle,
[tex]\cos (45^\circ)=\dfrac{7}{x}[/tex]
[tex]\dfrac{1}{\sqrt{2}}=\dfrac{7}{x}[/tex] [tex][\because \cos (45^\circ)=\dfrac{1}{\sqrt{2}}][/tex]
On cross multiplication, we get
[tex]1\times x=7\times \sqrt{2}[/tex]
[tex]x=7\sqrt{2}[/tex]
Therefore, the value of x is [tex]7\sqrt{2}[/tex] units.
