Answer: The final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml is 0.017 M
Explanation:
According to the dilution law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of stock [tex]CuSO_4[/tex] solution = 2.5 M
[tex]V_1[/tex] = volume of stock [tex]CuSO_4[/tex]solution = 5 ml
[tex]M_1[/tex] = molarity of diluted [tex]CuSO_4[/tex] solution = ?
[tex]V_1[/tex] = volume of diluted [tex]CuSO_4[/tex] solution = 750 ml
Putting in the values we get:
[tex]2.5\times 5=M_2\times 750[/tex]
[tex]M_2=0.017[/tex]
Therefore the final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml is 0.017 M