In ΔHIJ, i = 6.6 inches, j = 6.4 inches and ∠H=62°. Find the length of h, to the nearest 10th of an inch.

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Answer:

6.7

Step-by-step explanation:

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Law of cosine helps us to know the third side of a triangle. The length of the third side of the ΔHIJ, h is 6.698 inches.

What is the Law of Cosine?

The law of cosine helps us to know the third side of a triangle when two sides of the triangle are already known the angle opposite to the third side is given. It is given by the formula,

[tex]c =\sqrt{a^2 + b^2 -2ab\cdot Cos\theta}[/tex]

where

c is the third side of the triangle

a and b are the other two sides of the triangle,

and θ is the angle opposite to the third side, therefore, opposite to side c.

As it is given that the length of the first two sides of the triangle is i=6.6inches and j=6.4 inches, while the measure of the ∠H=62°. Therefore,

the length of the third side with the help of cosine rule can be written as,

[tex]h =\sqrt{i^2 + j^2 -2ij\cdot Cos(\angle H)}\\\\h =\sqrt{(6.6)^2 + (6.4)^2 -(2 \times 6.6 \times 6.4)\cdot Cos(62^o)}\\\\h = 6.6976 \approx 6.698[/tex]

Hence, the length of the third side of the ΔHIJ, h is 6.698 inches.

Learn more about the Law of Cosine:

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