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In the triangle below, ∠Q is a right angle. Which ratio would be equivalent to the ratio of sin∠R?
a) cos∠Q
b) cos∠S
c) sin∠Q
d) sin∠S

In the triangle below Q is a right angle Which ratio would be equivalent to the ratio of sinR a cosQ b cosS c sinQ d sinS class=

Respuesta :

mhanifa

Answer:

  • b) cos∠S

Step-by-step explanation:

sin ∠R = SQ/SR

This is same as:

  • cos S

Correct option is b)

cos<Q

Lets do

[tex]\\ \sf\longmapsto sin<R=\dfrac{P}{H}[/tex]

[tex]\\ \sf\longmapsto sin<R=\dfrac{SQ}{SR}[/tex]

Now

[tex]\\ \sf\longmapsto cos<Q=\dfrac{B}{H}[/tex]

[tex]\\ \sf\longmapsto cos<Q=\dfrac{SQ}{SR}[/tex]

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