If the magnetic force is 3.5 × 10–2 N, how fast is the charge moving?

The speed of the charge at the given magnetic force and field is determined as 1.1 x 10⁴ m/s.
The speed of the charge is calculated as follows;
F = qvBsinθ
v = F/qBsinθ
where;
v = (3.5 x 10⁻²)/(8.4 x 10⁻⁴ x 6.7x 10⁻³ x sin35)
v = 10,842.33 m/s
v ≅ 1.1 x 10⁴ m/s
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