Answer:
the distance is 12 units
Step-by-step explanation:
5 and 5 are the same so we don't use those digits,
-6 and 6 are different so we use them
since - 6 and 6 are both in different quadrants we take the absolute value of both of them and add,
|-6| + |6| = |6| + |6| = 12,
therefore the distance between C: (5,-6) and D: (5,6) is 12 units. hope i helped you (and could i have brainliest if possible?)
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Explanation:
The x coordinates are the same (both are 5), so we just focus on the y coordinates.
The y coordinates are y = -6 and y = 6. Subtract the two values and apply absolute value to find the distance. Let's say A = -6 and B = 6.
|A-B| = |-6-6| = |-12| = 12
or we could say
|B-A| = |6-(-6)| = |6+6| = |12| = 12
Either way, we get the same answer. The order of subtraction doesn't matter if we apply absolute value.
On a graph, plotting the two points (5,-6) and (5,6) will show that there's 12 units of space between them.
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If you wanted, you could apply the distance formula like so:
(x1,y1) = (5,-6)
(x2,y2) = (5,6)
[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(5-5)^2 + (-6-6)^2}\\\\d = \sqrt{(0)^2 + (-12)^2}\\\\d = \sqrt{0 + 144}\\\\d = \sqrt{144}\\\\d = 12\\\\[/tex]
Though in my opinion, I think the distance formula is overkill for this situation.
