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A cylinder of gas is at room temperature (20°C). The air conditioner breaks down, and the temperature rises
to 46°C. What is the new pressure of the gas relative to its initial pressure (Pi)?

Respuesta :

joyceart00

Answer: we divide this equation by pV and use {C}_{p}={C}_{V}+ . ... The temperature, pressure, and volume of the resulting gas-air mixture

Explanation:

Eduard22sly

The new pressure of the gas relative to its initial pressure P₁ is P₁ × 1.09

From the question given above, the following data were obtained:

Initial temperature (T₁) = 20 °C = 20 + 273 = 293 K

Initial pressure (P₁) = P₁

New temperature (T₂) = 46 °C = 46 + 273 = 319 K

New pressure (P₂) =?

The new pressure of the gas can be obtained as follow:

P₁ / T₁ = P₂ / T₂

P₁ / 293 = P₂ / 319

Cross multiply

293 × P₂ = P₁ × 319

Divide both side by 293

P₂ = (P₁ × 319) / 293

P₂ = P₁ × 1.09

Thus, the new pressure relative to it's initial pressure is P₁ × 1.09

Learn more: https://brainly.com/question/25547148

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