The label on the back of a microwave oven displays: frequency = 2450 MHz. If v = 3x10⁸ m/s, what is the wavelength of the microwaves and what is the period (time taken)? *

Respuesta :

Answer:

Wavelength, [tex]\lambda=0.122\ m[/tex] and [tex]t=4.08\times 10^{-10}\ s[/tex]

Explanation:

Given that,

The frequency of a microwave, f = 2450 MHz

We need to find the wavelength and the period of the microwaves.

The relation between the wavelength and frequency is given by :

[tex]c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{2450\times 10^6}\\\\\lambda=0.122\ m[/tex]

The period of the wave will be given by :

[tex]T=\dfrac{1}{f}\\\\T=\dfrac{1}{2450\times 10^6}\\\\T=4.08\times 10^{-10}\ s[/tex]

So, the wavelength and the time period of the wave be 0.122 m and [tex]4.08\times 10^{-10}\ s[/tex] respectively.