Answer:For the first one, it should be f(a)=37.8(1-cos(a))+.7. My dearest apologies because I do not know why. I just used context from the previous questions. I hope that helps..!
Step-by-step explanation:
The height of the given Ferris wheel can be described with the aid of a
sinusoidal function.
The height above the ground in terms of the angle turned, a, is
presented as follows;
The height above the ground in terms of the distance traveled, s, is
presented as follows;
Reason:
The general form of an equation of a Ferris wheel is presented as follows;
f(a) = A·sin(a + C) + D
Where, the amplitude, A = The radius = 37 ft.
D = The midline = Height above the ground + The amplitude
D = A + 0.6 = 37 + 0.6 = 37.6
The 6 O'clock is the lower most position, therefore, at the start, where, 'B·t + C' = 0, we have;
f(a) = A·sin(0 + C) + D
Therefore
f(a) = 37·sin(0 + C) + 37.6 = 0.6
f(a) = 37·sin(C) = 0.6 - 37.6 = -37
[tex]sin(C) = \dfrac{-37}{37} = -1[/tex]
C = sin⁻¹(-1) = [tex]-\dfrac{\pi}{2}[/tex]
The equation of Ferris wheel is presented as follows;
Which gives the equation of the height above the ground (in feet) in terms
of the number of radians, a, you have swept out from the 6 O'clock
position is given as follows; Ferris ;
Part 2
s = a·r = a·A
Therefore;
[tex]a = \dfrac{r}{s} = \dfrac{A}{s} = \dfrac{37}{s}[/tex]
Plugging the value of s into the above equation gives the function that
determines the height above the ground (in feet) in terms of the number of
feet traveled g(s) as follows;
Learn more here:
https://brainly.com/question/23844627
