The magnitude of power the monkey demonstrated is equal to 392 J/S.
Power calculation
To measure the power of a given body, one must relate its weight, the displacement performed and the time in which the movement was performed, in such a way:
[tex]P = \frac{m\times g\times d}{t}[/tex]
Thus, applying the values given by the statement we have:
[tex]P = \frac{80 \times 9.8 \times 15}{30}[/tex]
[tex]P = 392 J/s[/tex]
So, the power performed by the monkey climbing 15 meters is equal to 392J/s.
Learn more about power in: brainly.com/question/8671146
