Answer:
2 × 10²⁴ atoms Co
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Explanation:
Step 1: Define
4 mol Co (Cobalt)
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
- Set up: [tex]\displaystyle 4 \ mol \ Co(\frac{6.022 \cdot 10^{23} \ atoms \ Co}{1 \ mol \ Co})[/tex]
- Multiply/Divide: [tex]\displaystyle 2.4088 \cdot 10^{24} \ atoms \ Co[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 1 sig fig.
2.4088 × 10²⁴ atoms Co ≈ 2 × 10²⁴ atoms Co
