Answer:
110°
Step-by-step explanation:
In triangle AOB
OA = OB (radii of same circle)
[tex] m\angle OAB = m\angle OBA =20\degree [/tex]
[tex] m\angle AOB = 180\degree - (20\degree +20\degree) [/tex]
[tex] m\angle AOB = 180\degree - 40\degree [/tex]
[tex] m\angle AOB = 140\degree [/tex]
[tex] m\widehat {ACB} =m\angle AOB = 140\degree[/tex]
(measure of minor arc is equal to corresponding central angle)
[tex] x\degree = \frac{1}{2} (360\degree - 140\degree) [/tex]
(inscribed angle theorem)
[tex] x\degree = \frac{1}{2} \times 220\degree [/tex]
[tex]\huge\purple {x = 110} [/tex]
