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A baseball is thrown straight upward with a speed of 30 m/s. (a) How long will it rise? (b) How high will
it rise? (c) How long after it leaves the hand will it return to the starting point? (d) When will its speed be
16 m/s? Ans. (a) 3.1 s; (b) 46 m; (c) 6.1's; (d) 1.4 s and 4.7 s​

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Step-by-step explanation:

a) Time to max. height = (v/g) = 30/9.8 = 3.06 secs.

b)  Height attained = (v^2/2g) = 30^2/19.6 = 45.92 metres.

c) (3.06 x 2) = 6.12 secs.

d) Time to 16m/sec = (v/g) = 16/9.8 = 1.633 secs. Add 3.06 secs. if you need it to be time from release and then dropping to 16m/sec.

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