Answer:
4.41seconds later
Step-by-step explanation:
Let the equation of the height reached by the water front be h = -2t^2+7t+4
The water hits the ground at h =0
Substitute
0 = -2t^2+7t+4
-2t^2+7t+4 = 0
2t^2 - 7t - 8 = 0
t = 7±√(-7)²-4(2)(-8)/2(2)
t = 7±√49+64/4
t = 7±√113/4
t = 7±10.63/4
t = 7+10.63/4
t = 17.3/4
t = 4.41s
Hence the water hit the ground 4.41seconda later
