[tex]40 = k(10) \div {4}^{2} [/tex]
[tex] \frac{40}{10} = \frac{k(10) \div {4}^{2} }{10} [/tex]
[tex]4 = k \div {4}^{2} [/tex]
[tex]4 \times {4}^{2} = k \div {4}^{2} \times {4}^{2} [/tex]
[tex]64 = k[/tex]
//
[tex]216 = k {(3)}^{2}(12)[/tex]
[tex] \frac{216}{ {(3)}^{2}(12) } = \frac{k {(3)}^{2}(12) }{ {(3)}^{2}(12)} [/tex]
[tex]2 = k[/tex]
//
[tex]72 = k {(2}^{2}) {(3}^{2})[/tex]
[tex] \frac{72}{ {(2}^{2}) {(3}^{2}) } = \frac{k {(2}^{2}) {(3}^{2} ) }{ {(2}^{2}) {(3}^{2}) } [/tex]
[tex]2 = k[/tex]
//
[tex]90 = k(15)(2)[/tex]
[tex] \frac{90}{(15)(2)} = \frac{k(15)(2)}{(15)(2)} [/tex]
[tex]3 = k[/tex]
//
[tex]10 = k(2)[/tex]
[tex] \frac{10}{(2)} = \frac{k(2)}{(2)} [/tex]
[tex]5 = k[/tex]
//
Okay, it's pretty much the same process. That's all I can do. good luck!
