imrove
contestada

ten times the smallest of three consecutive integers is twenty two more than three times the sum of the integers. find the integers​

Respuesta :

timo86

Answer:

31, 32 and 33

Step-by-step explanation:

Mark these consecutive integers as (n-1), n and (n+1)

(n-1) is the smallest of them

Now write the equation

10 * (n-1) = 3 * (n-1 + n + n+1) + 22

10n - 10 = 3 * (n + n + n) + 22

10n - 10 = 3 * 3n + 22

10n - 10 = 9n + 22

10n - 9n = 22 + 10

n = 32

Now find these three integers

n-1 = 32 - 1 = 31

n = 32

n+1 =32 + 1 =33

Otras preguntas