A bicycle rides in a straight line at 1 km at 10
km/h and then another 1 km at 25 km/h what is the average speed of the bicycle

Respuesta :

Answer:

avg speed =total distance/total time

total distance =2km (given)

total time=1/10 +1/25=7/50

so avg speed =100/7=14.28

When a bicycle rides in a straight line at 1 km at 10 km/h and then another 1 km at 25 km/h then the average speed of the bicycle is 14.28 km /h

What is speed?

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is meter/second. The generally considered unit for speed is a meter per second.

The mathematical expression for speed is given by

average speed = total distance /Total time

As given in the problem a bicycle rides in a straight line at 1 km at 10 km/h and then another 1 km at 25 km/h

The total distance covered by the bicycle is

S =1 km +1 km

=2 km

The time is taken by bicycle on the first ride

T₁ = 1 km / 10 km/h

T₁ = 1/10 h

The time is taken by bicycle on the second ride

T₂ = 1 km /25 km/h

T₂= 1/25 h

Then by using the formula for the average speed

Average speed = total distance /Total time

By substituting the respective values of the total distance and total time

average speed = 2 / ( 1/10 + 1/25)

                          =14.28 km /h

Thus, the average speed of the bicycle comes out to be 14.28 km /h

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brainly.com/question/7359669

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