Respuesta :
Answer:
100. mL
Explanation:
Step 1: Write the balanced equation for the double displacement reaction
CaCl₂ + Na₂CO₃ ⇒ 2 NaCl + CaCO₃
Step 2: Calculate the moles corresponding to 1.00 g of CaCO₃
The molar mass of CaCO₃ is 100.09 g/mol.
1.00 g × 1 mol/100.09 g = 0.0100 mol
Step 3: Calculate the moles of CaCl₂ required to produce 0.0100 moles of CaCO₃
The molar ratio of CaCl₂ to CaCO₃ is 1:1. The moles of CaCl₂ required are 1/1 × 0.0100 mol = 0.0100 mol.
Step 4: Calculate the volume of 0.100 M CaCl₂ that contains 0.0100 mol
0.0100 mol × 1 L/0.100 mol × 1000 mL/1 L = 100. mL
The volume of calcium chloride required has been 100 mL.
The balanced chemical equation for the reaction has been:
[tex]\rm CaCl_2\;+\;Na_2CO_3\;\rightarrow\;2\;NaCl\;+\;CaCO_3[/tex]
According to the balanced chemical equation, for producing 1 mole of calcium carbonate, 1 mole of calcium chloride has been required.
Computation for Volume of Calcium Chloride
The mass of calcium carbonate to be produced has been 1 gram. Thus the moles of calcium carbonate has been:
[tex]\rm Moles=\dfrac{Mass}{Molar\;mass} \\Moles\;CaCO_3=\dfrac{1}{100}\\ Moles\;CaCO_3=0.010\;mol[/tex]
The moles of calcium carbonate to be produced has been 0.01 mol.
The moles of calcium chloride required has been:
[tex]\rm 1\;mol\;CaCO_3=1\;mol\;CaCl_2\\0.01\;mol\;CaCO_3=0.01\;mol\;CaCl_2[/tex]
The moles of calcium chloride required has been 0.01 mol.
The given molarity of the sample has been 0.1 M.
The volume of the sample has been given by:
[tex]\rm Molarity=\dfrac{Moles}{Volume\;(L)}\\ 0.1\;M=\dfrac{0.01}{Volume\;(L)}\\Volume=100\;ml[/tex]
The volume of calcium chloride required has been 100 mL.
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