Respuesta :
Answer:
a) 0.0835 = 8.35% of students at the university are statistics majors
b) 0.8623 = 86.23% are at the Main campus
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
This is used for item b.
a. What proportion of students at the university are statistics majors?
12% of 60%(At the main campus).
4% of 25%(Downtown campus).
The rest is 100 - 60 + 25) = 15%.
1% of 15%(Bay Area Campus). Si
[tex]p = 0.12*0.6 + 0.04*0.25 + 0.01*0.15 = 0.0835[/tex]
0.0835 = 8.35% of students at the university are statistics majors.
b. Of all statistics majors at the university, what proportion are at the Main campus?
Using conditional probability to find the percentage.
Event A: Statistics majors, so [tex]P(A) = 0.0835[/tex]
Event B: Main Campus
Intersection of A and B:
12% of 60%. So
[tex]P(A \cap B) = 0.12*0.6 = 0.072[/tex]
Percentage:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.072}{0.0835} = 0.8623[/tex]
0.8623 = 86.23% are at the Main campus
