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Find the concentration of the saline solution in terms of % by mass using your exact mass of NaCl, the volume of water (80.0 mL), and density of water being 0.9981 g/mL
1) Calculate the predicted (theoretical) concentration of the saline solution in terms of % by mass using your exact mass of NaCl, the volume of water (80.0 mL), and density of water being 0.9981 g/mL. Show the calculation in detail with the corresponding units of measurement and the appropriate sig. figs. The mass of NaCl used was 17.518 g.
2) Use the information to calculate the experimental value for the concentration (% by mass) of your saline solution based on your experimental value for density obtained with the volumetric pipette. You must show ALL the work and the calculation leading to the result in detail for full credit. The graph equation given is y=(0.0076x) + (0.9935) where y= density, x= Concentration and the density of solution using one experimental value for volumetric pipette;1.08

Respuesta :

Answer:

1) Theoretical Concentration = 17.992%

2) Experimental Concentration = 11.382%

Explanation:

Data Given:

Mass of NaCl = 17.518 g

Volume of Water = 80 mL

Density of Water = 0.9981 g/mL

Mass of water = 80 mL x [tex]\frac{0.9981 g}{mL}[/tex]

1)

Mass of Water = 79.848 g

The formula for concentration is:

Concentration = [tex]\frac{Mass of NaCl}{Mass of Water + Mass of NaCl}[/tex] x 100%

Plugging in the values:

Concentration = [tex]\frac{17.518 g }{79.848 g + 17.518 g}[/tex] x 100%

Concentration = 17.992%

2)

Given Data:

Experimental Value of Density = 1.08 g/mL

The graph equation is given as:

y = (0.0076x) + (0.9935)

where,

y = density, x = concentration.

Plugging in the values into the equation, we get:

1.08 = (0.0076) x + 0.9935

1.08 - 0.9935 = (0.0076)x

x = 11.382%

Hence,

The experimental value of concentration of saline solution is 11.382%

1)  The predicted (theoretical) concentration of the saline solution in terms of % by mass is; 18%

2) The experimental value for the concentration (% by mass) is; 11.38%

Concentration of Solutions

We are given;

Mass of NaCl = 17.518 g

Volume of Water = 80 mL

Density of Water = 0.9981 g/mL

Formula for mass is; mass = volume * density

Thus;

Mass of water = 80 mL * 0.9981 g/mL

Mass of water = 79.848 g

1) To find the theoretical concentration of the saline solution, we will use the formula;

Theoretical concentration = [(Mass of NaCl)/(Mass of NaCl  + Mass of Water)] * 100%

Theoretical concentration = [17.518/(17.518 + 79.848)] * 100%

Theoretical Concentration = 0.18 0r 18%

2) We are given;

Experimental Value of Density = 1.08 g/mL

The graph equation;

y = (0.0076x) + (0.9935)

where,

y = density and x = concentration.

Plugging in the relevant values, we have;

1.08 = (0.0076)x + 0.9935

1.08 - 0.9935 = (0.0076)x

0.0865 = 0.0076x

x = 0.0865/0.0076

x = 11.38 %

Thus; experimental value for the concentration (% by mass) of your saline solution is 11.38%

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