Answer:
See answer below
Explanation:
In this case, we are treating an alcohol with different reagents to give different products. In the picture below you have the draw of each product, and here, the explanation.
a) H₂SO₄: In this case, it will promote an E1 reaction forming an alkene as product.
b) NaH: In this case, it will promote an acid base reaction, and the final product will be an alcoxide.
c) HCl/ZnCl₂: In this case, primary alcohols reacts with this reactive to form an alkyl halide.
d) HBr: Another reaction forming an alkyl halide with bromine in this case.
e) SOCl₂: Similar to c), it will form an alkyl chloride.
f) PBr₃: Similar to d, forming an alkyl bromide.
g) TsCl: Here it will be a sustitution reaction, where tosilate replaces the OH
h) NaH/CH₃CH₂Br: In this case it will form an alcoxide and then, a larger alkyl.
i) TsCl/NaSH: First it will form a tosilate and then, the SH group. A sustitution reaction.
j) POCl₃: A sustitution reaction forming an alkyl chloride.
See picture below for drawings.
Hope this helps
