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Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below.

2NaClO3 --> 2NaCl +3O2

How many moles of NaClO3 were needed to produce 7 moles of O2?

Round your answer to the nearest whole number.


I need help with this so bad, otherwise I’m 100% going to fail the quiz, thank you!!

Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below 2NaClO3 gt 2NaCl 3O2 How many moles of NaClO3 were needed to produ class=

Respuesta :

Rasco

Answer:

4.62

so 5

the ratio is 2 na chlorates for 3 O2 so multiply 7 by 2/3

Explanation:

Oseni

The number of moles of  NaClO3 that would be needed to produce 7 moles of O2 would be 5 moles of NaClO3 approximately.

Stoichiometric calculations

From the equation of the reaction:

2NaClO3 --> 2NaCl +3O2

The mole ratio of NaClO3 to O2 is 2:3.

Thus, every 3 moles of O2 require 2 moles of NaClO3 .

7 moles of O2 will, therefore require:

                                     = 2 x7/3

                                              = 4.6666 moles of NaClO3

To the nearest whole number = 5 moles of NaClO3

More on stoichiometric calculations can be found here: https://brainly.com/question/8062886

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