Answer:
The right response is "1.6 m/s²".
Explanation:
The given values are:
Length of the pendulum,
= 1.5 m
Time period,
= 6.0837 seconds
As we know,
⇒ [tex]T = 2\pi \sqrt{\frac{L}{g} }[/tex]
On substituting the given values, we get
⇒ [tex]6.0837 = (2\times 3.14) \sqrt{\frac{1.5}{g}[/tex]
⇒ [tex]6.0837=6.28\sqrt{\frac{1.5}{g} }[/tex]
⇒ [tex]g= 1.6 \ m/s^2[/tex]
