Respuesta :
Answer:
95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college
(0.4958 , 0.7041)
Step-by-step explanation:
Step(i):-
Given that the sample size 'n' = 85
The sample proportion
[tex]p = \frac{x}{n} = \frac{51}{85} = 0.6[/tex]
95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college
[tex](p^{-} -Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} +Z_{0.05} \sqrt{\frac{p(1-p)}{n} })[/tex]
Step(ii):-
Given that the level of significance
α = 0.05
Z₀.₀₅ = 1.96
[tex](0.6 -1.96 \sqrt{\frac{06(1-06)}{85} } , 0.6 +1.96 \sqrt{\frac{0.6(1-0.6)}{85} })[/tex]
(0.6 - 0.104138 , 0.6 +0.104138)
(0.4958 , 0.7041)
Final answer:-
95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college
(0.4958 , 0.7041)
