Answer:
5 balls
Step-by-step explanation:
Given data
Diameter of ball= 2.6in
radius= 1.3 in
volume of ball= 4/3πr^3
Required
The number of balls that can be in the container
v=4/3*3.142*1.3^3
v= 4/3*3.142*2.197
v=27.61/3
v=9.20 in^3
The number of balls in the container is
=46.4/9.20
=5.04
Approximately 5 balls
