Answer:
[tex]49.47\ \text{m}[/tex]
Step-by-step explanation:
The distance between the guy wire and the base of the pole is [tex]48\ \text{m}[/tex]
The angle between the guy wire and the ground is [tex]14^{\circ}[/tex]
From the trigonometric ratios we have
[tex]\cos\theta=\dfrac{\text{Adjacent side}}{\text{Hypotenuse}}\\\Rightarrow \cos14^{\circ}=\dfrac{48}{x}\\\Rightarrow x=\dfrac{48}{\cos14^{\circ}}\\\Rightarrow x=49.47\ \text{m}[/tex]
The length of the guy wire is [tex]49.47\ \text{m}[/tex].
