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Report your answer with the proper number of significant figures. Magnesium is used in lightweight alloys for airplane bodies and other structures. The metal is obtained from seawater in a process that includes precipitation, neutralization, evaporation, and electrolysis. How many kilograms of magnesium can be obtained from 4.29 km3 of seawater if the initial Mg2 concentration is 0.19% by mass

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Answer:

8.47 * 10^9 Kg

Explanation:

Density of sea water = 1040 kg/m^3

mass of sea water = ?

Volume of sea water = 4.29 * 10^3 m^3

Mass of sea water = 1040 kg/m^3 * 4.29 * 10^9 m^3

Mass of sea water = 4.46 * 10^12 Kg

Mass of Mg2+ =  0.19% by mass

So;

Mass of Mg2+ =0.19/100 * 4.46 * 10^12 Kg

Mass of Mg2+ = 8.47 * 10^9 Kg

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