Answer:
0.011 N-m
Explanation:
Given that
The mass of a solid cylinder, m = 30 kg
The radius of the cylinder, r = 0.18 m
The acceleration of the cylinder, [tex]\alpha =0.023\ rad/s^2[/tex]
It rotates about an axis through its center. We need to find the torque acting on the cylinder. The formula for the torque is given by :
[tex]\tau=I\alpha[/tex]
Where
I is the moment of inertia of the cylinder,
For cylinder,
[tex]I=\dfrac{mr^2}{2}[/tex]
So,
[tex]\tau=\dfrac{mr^2\alpha }{2}\\\\\tau=\dfrac{30\times (0.18)^2\times 0.023 }{2}\\\\\tau=0.011\ N-m[/tex]
So, the required torque on the cylinder is 0.011 N-m.
