Respuesta :

Space

Answer:

78 L Cl₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

280 g Cl₂

Step 2: Identify Conversions

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.90 g/mol

[STP] 1 mol = 22.4 L

Step 3: Convert

  1. [DA] Set up:                                                                                                   [tex]\displaystyle 280 \ g \ Cl_2(\frac{1 \ mol \ Cl_2}{79.90 \ g \ Cl_2})(\frac{22.4 \ L \ Cl_2}{1 \ mol \ Cl_2})[/tex]
  2. [DA] Multiply/Divide [Cancel out units]:                                                       [tex]\displaystyle 78.4981 \ L \ Cl_2[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

78.4981 L Cl₂ ≈ 78 L Cl₂

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