Light from three different lasers (A, B, and C), each with a different wavelength, was shined onto the same metal surface. Laser A produced no photoelectrons. Lasers C and B both produced photoelectrons, but the photoelectrons produced by laser C had a greater velocity than those produced by laser B. Arrange the lasers in order of increasing wavelength.

The wavelength of the laser is inversely proportional to the frequency of the laser. The kinetic energy of the photoelectrons depends on the frequency of the light. Work function of a metal surface is constant.

[tex]K.E. = h\nu-\phi[/tex] where, [tex]h\nu[/tex] is the incident energy and [tex]\phi[/tex] is the work function of the metal surface.

Thus, greater the incidence energy, greater would be the velocity of the photoelectrons.

Laser A produced no photoelectrons. It means it has least energy (least frequency) and hence, greatest wavelength.

laser C cause greater velocity of photo electrons than that b y B.

[tex]\lambda_C<\lambda_B<\lambda_A[/tex]

Thus, lasers in order of increasing wavelength are:

C<B<A

pstnonsonjoku pstnonsonjoku · Answer 2 · 2021-10-31T18:22:07+01:00

The order of increasing wavelength for the lasers is; C < B < A.

Albert Einstein discovered the phenomenon commonly referred to as photoelectric effect. This is the ejection of electrons from a clean metal surface when light of appropriate wavelength or frequency shines on it. There is a minimum frequency of photons for which photoelectrons can be emitted from the metal surface. This is called the threshold frequency.

We know that the energy and wavelength of waves are inversely proportional. The photons that produced the greater velocity of photoelectrons certainly possesses greater energy and shorter wavelength. Hence, the order of increasing wavelength for the lasers is; C < B < A.

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